document.write( "Question 1043938: Solve the system using the substitution method. If the system has no solution or an infinite number of solutions, state this.\r
\n" ); document.write( "\n" ); document.write( "x+y=7
\n" ); document.write( "6x+6y=42
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Algebra.Com's Answer #659149 by ikleyn(52794)\"\" \"About 
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\n" ); document.write( "Solve the system using the substitution method. If the system has no solution or an infinite number of solutions, state this.\r
\n" ); document.write( "\n" ); document.write( "x+y=7
\n" ); document.write( "6x+6y=42
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document.write( "Divide the second equation by 6 (both sides),\r\n" );
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document.write( "and you will see that this equation become \r\n" );
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document.write( "x + y = 7,\r\n" );
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document.write( "exactly as the first equation is.\r\n" );
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document.write( "So, you have here the system of two equivalent (depending) equations.\r\n" );
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document.write( "The system has infinitely many solutions.\r\n" );
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