document.write( "Question 1043926: joan has one solution that is 18% acid and
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document.write( "second solution that is 43% acid.How many
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document.write( "liters should she mix together in order to get
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document.write( "an 80 liters solution that is 26.5% acid \n" );
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Algebra.Com's Answer #659136 by josmiceli(19441)![]() ![]() You can put this solution on YOUR website! Let \n" ); document.write( "Let \n" ); document.write( "----------------------------------- \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "----------------------------------- \n" ); document.write( "(1) \n" ); document.write( "(2) \n" ); document.write( "----------------------------------- \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "--------------------------- \n" ); document.write( "Multiply both sides of (1) by \n" ); document.write( "and subtract (1) from (2) \n" ); document.write( "(2) \n" ); document.write( "(1) \n" ); document.write( "-------------------------- \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "and \n" ); document.write( "(1) \n" ); document.write( "(1) \n" ); document.write( "---------------------- \n" ); document.write( "52.8 liters of 18% solution are needed \n" ); document.write( "27.2 liters of 43% solution are needed \n" ); document.write( "-------------------------------- \n" ); document.write( "check answer: \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "OK \n" ); document.write( " |