document.write( "Question 1043924: find the point of intersection of x^2+y^2=25,
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Algebra.Com's Answer #659127 by ikleyn(52799)\"\" \"About 
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document.write( "\"x%5E2+%2B+y%5E2\" = 25,   (1)\r\n" );
document.write( "\"x%5E2%2F18+%2B+y%5E2%2F32\" = 1.    (2)\r\n" );
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document.write( "Multiply (2) by 18 (both sides). You will get\r\n" );
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document.write( "\"x%5E2+%2B+y%5E2\" = 25,        (1')\r\n" );
document.write( "\"x%5E2+%2B+y%5E2%2818%2F32%29\" = 18,   (2')\r\n" );
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document.write( "or equivalently\r\n" );
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document.write( "\"x%5E2+%2B+y%5E2\" = 25,        (1'')\r\n" );
document.write( "\"x%5E2+%2B+y%5E2%289%2F16%29\" = 18.   (2'')\r\n" );
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document.write( "Distract (2'') from (1''). You will get\r\n" );
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document.write( "\"y%5E2%281-9%2F16%29\" = 25 - 18,  or  \"%287%2F16%29y%5E2\" = 7,  or \"y%5E2\" = 16.\r\n" );
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document.write( "Hence, y = +/- 4.\r\n" );
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document.write( "Then from (1) x = +/-3.\r\n" );
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document.write( "Answer. There are four solution and, respectively, four intersection points:\r\n" );
document.write( "        (x,y) = (3,4), (3,-4), (-3,-4), (-3, 4).\r\n" );
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