document.write( "Question 1043919: A cylindrical vessel has a base-radius of 10cm. It contains water to a depth of 12cm. A metal pipe whose inner and outer radii are 4cm and 6cm respectively rests vertically on the base of the vessel. LLet h the final height of the water level as in the picture, make an equation and find h. Hence, find the rise in the water level.\r
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Algebra.Com's Answer #659116 by ikleyn(52797)\"\" \"About 
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\n" ); document.write( "A cylindrical vessel has a base-radius of 10 cm. It contains water to a depth of 12 cm. A metal pipe whose inner and outer radii
\n" ); document.write( "are 4 cm and 6 cm respectively rests vertically on the base of the vessel. Let h the final height of the water level as in the picture,
\n" ); document.write( "make an equation and find h. Hence, find the rise in the water level.
\n" ); document.write( "I really don't get what the question is asking for!
\n" ); document.write( "If they give us the height/depth at the beginning, isn't it the same at the end? What rise???
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document.write( "When you submerge a solid body into the liquid in the vessel, the body displaces liquid and makes its level higher.\r\n" );
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document.write( "This phenomenon is known for thousands years, and one of famous Archimedes achievement was to find the density of the king's crown \r\n" );
document.write( "made of unknown material by submerging it into water.\r\n" );
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document.write( "OK. Now let us return to our problem.\r\n" );
document.write( "This time we have cylindrical hollow tube placed into water in the vessel vertically.\r\n" );
document.write( "The initial level of the water in the vessel was h = 12 cm. \r\n" );
document.write( "Then the liquid volume in the vessel is V = \"pi%2AR%5E2%2Ah\"  \"cm%5E3\".\r\n" );
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document.write( "Let \"H\" be the raised level of the water in the vessel after the tube submerging.\r\n" );
document.write( "The area of the space occupied by water is \"pi%2AR%5E2+-+%28pi%2Ar%5Bout%5D%5E2+-+pi%2Ar%5Bin%5D%5E2%29\".\r\n" );
document.write( "I distracted from \"pi%2AR%5E2\" the area of the tube cross section.\r\n" );
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document.write( "The volume of water remains unchangeable. It gives you an equation\r\n" );
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document.write( "\"pi%2AR%5E2%2Ah\" = \"%28pi%2AR%5E2+-+%28pi%2Ar%5Bout%5D%5E2+-+pi%2Ar%5Bin%5D%5E2%29%29%2AH\".\r\n" );
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document.write( "It is your equation to determine H. Solve it for H:\r\n" );
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document.write( "H = \"%28pi%2AR%5E2%2Ah%29%2F%28pi%2AR%5E2+-+%28pi%2Ar%5Bout%5D%5E2+-+pi%2Ar%5Bin%5D%5E2%29%29\".\r\n" );
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document.write( "Now substitute values (and cancel \"pi\"):\r\n" );
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document.write( "H = \"%2810%5E2%2A12%29%2F%2810%5E2+-+%286%5E2+-+4%5E2%29%29\" = \"%28100%2A12%29%2F%28100+-+%2836-16%29%29\" = \"%28100%2A12%29%2F%28100-20%29\" = \"%28100%2A12%29%2F80\" = \"12%2A%285%2F4%29\" = 15 cm.\r\n" );
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document.write( "Answer. The raised water level after the tume submerging vertically is 15 cm.\r\n" );
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