document.write( "Question 1043857: A girl starts from a point A and walks 285m to B on a bearing of 078°. she then walks due south u a point C which is 307m for A. what is the bearing of A from C, and what is |BC| \n" ); document.write( "
Algebra.Com's Answer #659107 by Boreal(15235)\"\" \"About 
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\n" ); document.write( "|------------B
\n" ); document.write( "A------------|D
\n" ); document.write( "|
\n" ); document.write( "|
\n" ); document.write( "|------------C
\n" ); document.write( "A to B is 285
\n" ); document.write( "That is the hypotenuse of the triangle ADB, which is a right triangle if AD has bearing 090 degrees.
\n" ); document.write( "Angle A is 12 degrees, since the bearing to B was 78 degrees.
\n" ); document.write( "From that we can get the value of BD. which is the sine of angle A.
\n" ); document.write( "sin A=BD/285
\n" ); document.write( "BD=285*sin A=59.25 m
\n" ); document.write( "CA has length 307
\n" ); document.write( "cos A is AD/AB; AD is AB cos 12=278.77 m
\n" ); document.write( "sin C=AD/AC=278.77/307=0.9080.
\n" ); document.write( "sin^(-1) (0.9080)=65.24 degrees. This bears west of north, so that the bearing from C to A is -65.24 degrees or 294.36 degrees. ANSWER
\n" ); document.write( "CD/AC is the cosine of angle C
\n" ); document.write( "cos 65.24=CD/AC
\n" ); document.write( "307 cos 65.24=CD
\n" ); document.write( "CD=128.58 m
\n" ); document.write( "Therefore BC=128.58+59.25=187.83 m ANSWER \n" ); document.write( "
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