document.write( "Question 1043887: If anyone could help me with these four questions that would be great!\r
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Algebra.Com's Answer #659085 by rothauserc(4718) You can put this solution on YOUR website! 1) False \n" ); document.write( "The sum of any two sides of a triangle must be greater than the third \n" ); document.write( ": \n" ); document.write( "2) False \n" ); document.write( "see 1) explanation and note that 5+6 < 12 \n" ); document.write( ": \n" ); document.write( "3) False \n" ); document.write( "hypotenuse of a right triangle is the longest side \n" ); document.write( ": \n" ); document.write( "4) \n" ); document.write( "diagonals bisect each other, therefore OB = 8 and BD = 16 \n" ); document.write( "a = 6, b = 12 \n" ); document.write( ": \n" ); document.write( "we have the following relationship between the diagonals and the sides of a parallelogram \n" ); document.write( ": \n" ); document.write( "BD^2 + AC^2 = 2(6^2 + 12^2) \n" ); document.write( ": \n" ); document.write( "256 + AC^2 = 2(180) = 360 \n" ); document.write( ": \n" ); document.write( "AC^2 = 104 \n" ); document.write( ": \n" ); document.write( "AC = 10.20 \n" ); document.write( ": \n" ); document.write( "************************************ \n" ); document.write( "False \n" ); document.write( "16(BD) is not greater than 10.20(AC) \n" ); document.write( "************************************ \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( " |