document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1043853>Question 1043853</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve: (x+2)^3(x-1)^2(x-3) less than or equal to 0 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #659030 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39620)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=659030\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Critical values give the intervals <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=system%28x%3C=-2%2C-2%3C=x%3C=1%2C1%3C=x%3C=3%2C3%3C=x%29 ALIGN=MIDDLE  ALT=\"system%28x%3C=-2%2C-2%3C=x%3C=1%2C1%3C=x%3C=3%2C3%3C=x%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >.\r<BR>\n" );
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document.write( "Check any value in each interval and determine sign of the expression.  Negative means \"less than or equal to zero\", as will 0.  Positive means \"not less than or equal to zero\".  The set of intervals which work (giving negative) is the solution set. </SPAN>\n" );
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