document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1043819>Question 1043819</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Divide 56 into two parts such that three times the first part exceeds one third of the second by 48. The parts are ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #658982 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=658982\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the first part is x<BR>\n" );
document.write( "the second part is 56-x.  <BR>\n" );
document.write( "3x-48 (three times the first exceeds, so subtract 48 to make it equal)=(1/3)(56-x)<BR>\n" );
document.write( "3x-48=(1/3)(56-x).  Multiply both sides by 3 to remove the fraction<BR>\n" );
document.write( "9x-144=56-x<BR>\n" );
document.write( "10x=200<BR>\n" );
document.write( "x=20, first part.<BR>\n" );
document.write( "3 times that is 60<BR>\n" );
document.write( "subtract 48 and it is 12<BR>\n" );
document.write( "that is 1/3 the second, so 3 times that is the second, and that is 36, second part.<BR>\n" );
document.write( "20 and 36 equal 56.\r<BR>\n" );
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