document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1043811>Question 1043811</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the population of a town increases every year by 2% ofa total population at the begining of that year, in how many year will the total increase of population be 40%? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #658969 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=658969\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> original is Po, final is P<BR>\n" );
document.write( "P=Po{1+.02}^n, the interest formula.<BR>\n" );
document.write( "P/Po=1.40<BR>\n" );
document.write( "1.40={1.02}^n<BR>\n" );
document.write( "ln of both sides<BR>\n" );
document.write( "ln(1.40)=n{ln (1.02))<BR>\n" );
document.write( "divide by ln 1.02<BR>\n" );
document.write( "ln(1.40)/ln(1.02)=16.99 years<BR>\n" );
document.write( "17 years.<BR>\n" );
document.write( "1.02^17=1.400<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );