document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1043807>Question 1043807</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If three less than one half a number is equal to one-third of the same number, find the number </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #658963 by </B><A HREF=/tutors/aboutme.mpl?userid=mpn292><B>mpn292(1)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mpn292><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=658963\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Sol: Let the number be 'x'<BR>\n" );
document.write( "     according to given question,<BR>\n" );
document.write( "     (x/2)-3=x/3<BR>\n" );
document.write( "     now set all the fractions on one side and constants on other side<BR>\n" );
document.write( "     i.e; (x/2)-(x/3)=3<BR>\n" );
document.write( "     now take the LCM of 2,3 and it is 6<BR>\n" );
document.write( "     (3x-2x)/6=3<BR>\n" );
document.write( "     (x/6)=3<BR>\n" );
document.write( "     x=6*3<BR>\n" );
document.write( "     x=18.<BR>\n" );
document.write( "     Therefore the number is, x=18.<BR>\n" );
document.write( " </SPAN>\n" );
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