document.write( "Question 90793: Please help me solve this problem.
\n" ); document.write( "Three times the measure of a complement of a certain angle is equal to 30 more than the measure of the supplement of that angle. Find the measure of each angle.
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Algebra.Com's Answer #65896 by malakumar_kos@yahoo.com(315)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( " Three times the measure of a complement of a certain angle is equal to 30 more than the measure of the supplement of that angle. Find the measure of each angle.\r
\n" ); document.write( "\n" ); document.write( " Let the angle be = x\r
\n" ); document.write( "\n" ); document.write( " its complement = 90-x\r
\n" ); document.write( "\n" ); document.write( " its supplement = 180-x\r
\n" ); document.write( "\n" ); document.write( " three times the complement = 30 more than its supplement\r
\n" ); document.write( "\n" ); document.write( " 3(90-x) = 30+(180-x)\r
\n" ); document.write( "\n" ); document.write( " 270 - 3x = 30+180-x\r
\n" ); document.write( "\n" ); document.write( " 270-180-30 = 3x-x\r
\n" ); document.write( "\n" ); document.write( " 270-210 = 2x\r
\n" ); document.write( "\n" ); document.write( " 60 = 2x\r
\n" ); document.write( "\n" ); document.write( " x = 60/2 = 30\r
\n" ); document.write( "\n" ); document.write( " The required two angles are 1)90-x = 90-30 = 60\r
\n" ); document.write( "\n" ); document.write( " 2)180-x = 180-30 = 150
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