document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1043779>Question 1043779</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a rectangle is formed by increasing one side fo the square by 5cm and reducing the adjacent side of the square by 3cm. if the perimeter of the rectangle is 40cm find the length of the squares side.\r<BR>\n" );
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document.write( "Please help me solve this. Thank you!\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #658944 by </B><A HREF=/tutors/aboutme.mpl?userid=blupooth><B>blupooth(1)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=blupooth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=blupooth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=658944\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2(x+5)+2(x-3)=40<BR>\n" );
document.write( "=2x+10+2x-6=40<BR>\n" );
document.write( "=4x+6=40<BR>\n" );
document.write( "4x=34<BR>\n" );
document.write( "x=<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=34%2F4 ALIGN=MIDDLE  ALT=\"34%2F4\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "x=8.5\r<BR>\n" );
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document.write( ":) </SPAN>\n" );
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