document.write( "Question 1043746: a box contains 4 red balls and 8 white balls. how much greater is the probability of simultaneously drawing 2 white balls at random than simultaneously drawing 2 red balls at random? \n" ); document.write( "

Algebra.Com's Answer #658899 by Boreal(15235) $\"\"$ $\"About$

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Two white balls at random without replacement is (8/12)*(7/11)=56/132, or 14/33.
\n" ); document.write( "Two red balls at random without replacement is (1/3)(3/11)=1/11
\n" ); document.write( "The difference (the amount greater) is 14/33-3/33=11/33, or 1/3. \n" ); document.write( "

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