document.write( "Question 1043698: x^2+y^2+z^2=2(x+z-1) then the value of x^3+y^3+z^3 \n" ); document.write( "
Algebra.Com's Answer #658858 by ikleyn(52835)\"\" \"About 
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\n" ); document.write( "x^2+y^2+z^2=2(x+z-1) then the value of x^3+y^3+z^3
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document.write( "If  \"x%5E2%2By%5E2%2Bz%5E2\" = \"2%28x%2Bz-1%29\",  then\r\n" );
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document.write( "\"x%5E2+-+2x+%2B+y%5E2+%2B+z%5E2+-+2z\" = \"-2\",\r\n" );
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document.write( "\"%28x-1%29%5E2+-+1+%2B+y%5E2+%2B+%28z-1%29%5E2+-+1\" = \"-2\",\r\n" );
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document.write( "\"%28x-1%29%5E2+%2B+y%5E2+%2B+%28z-1%29%5E2\" = \"0\".\r\n" );
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document.write( "We have the sum of squares of three real numbers equal to zero.\r\n" );
document.write( "Hence, each of the three numbers is equal to zero:\r\n" );
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document.write( "x-1 = 0,  y = 0  and  z-1 = 0.\r\n" );
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document.write( "In other words, x = 1, y = 0, z = 1.\r\n" );
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document.write( "Now \"x%5E3+%2B+y%5E3+%2B+z%5E3%7D%7D+=+%7B%7B%7B%28-1%29%5E3+%2B+0%5E3+%2B+%28-1%29%5E3\" = -2.\r\n" );
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