document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1043695>Question 1043695</A>: <I><SPAN STYLE=\"word-break: break-all;\"> P and Q are two points on the line x-y+1=0 and are at the distance 5 units from origin.Find the area of the triangle OPQ. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #658848 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=658848\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P and Q are two points on the line x-y+1=0 and are at the distance 5 units from origin.Find the area of the triangle OPQ.<BR>\n" );
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document.write( "x-y+1 = 0<BR>\n" );
document.write( "y = x+1<BR>\n" );
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document.write( "Slope = 1<BR>\n" );
document.write( "atan(1) = 45 degrees\r<BR>\n" );
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document.write( "P and Q are two points on the line x-y+1=0 and are at the distance 5 units from origin.<BR>\n" );
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document.write( "bb later to finsih.  The plumber is here.<BR>\n" );
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document.write( "find the 2 points P and Q<BR>\n" );
document.write( "It's the intersections of the line and the circle.<BR>\n" );
document.write( "y = x+1<BR>\n" );
document.write( "x^2 + y^2 = 5^2<BR>\n" );
document.write( "x^2 + (x+1)^2 = 25<BR>\n" );
document.write( "2x^2 + 2x - 24 = 0<BR>\n" );
document.write( "x^2 + x - 12 = 0<BR>\n" );
document.write( "(x+4)*(x-3) = 0<BR>\n" );
document.write( "x = -4, y = -3 --> (-4,-3)<BR>\n" );
document.write( "x = 3, y = 4 --> (3,4)<BR>\n" );
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document.write( "Pq = sqrt(diffy^2 + diffx^2) = 7sqrt(2)<BR>\n" );
document.write( "It's a triangle with sides of 5, 5 and 7sqrt(2)<BR>\n" );
document.write( "Use Heron's Law to find the area.<BR>\n" );
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document.write( "Or,<BR>\n" );
document.write( "Use point R at (3,-3) to from a right triangle PQR.<BR>\n" );
document.write( "The area of PQR is 7*7/2 = 49/2 sq units.<BR>\n" );
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document.write( "Subtract the area of triangle OQ(3,0) and the area of OP(0,-3), and subtract the area of the square. The square is 3 by 3 --> area = 9 sq units.\r<BR>\n" );
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