document.write( "Question 90799: evalute each function for the value specified:
\n" ); document.write( "f(x)= x (to the second power) - 7x +10,
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Algebra.Com's Answer #65883 by praseenakos@yahoo.com(507)\"\" \"About 
You can put this solution on YOUR website!
Question:\r
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\n" ); document.write( "\n" ); document.write( "evalute each function for the value specified:
\n" ); document.write( "f(x)= x (to the second power) - 7x +10,
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\n" ); document.write( "\n" ); document.write( "f(x) = \"x%5E2+-+7x+%2B+10+\"\r
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\n" ); document.write( "\n" ); document.write( "To find f(0), what you have to do is replace x by 0 in the given function.\r
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\n" ); document.write( "\n" ); document.write( "==> f(0) = \"0%5E2+-+7%2A0+%2B+10+\"\r
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\n" ); document.write( "\n" ); document.write( "==> f(0) = 0 - 0 + 10\r
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\n" ); document.write( "\n" ); document.write( "==> f(0) = 10\r
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\n" ); document.write( "\n" ); document.write( "Similarly...\r
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\n" ); document.write( "\n" ); document.write( "f(5) = \"5%5E2+-+7%2A5+%2B+10+\"\r
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\n" ); document.write( "\n" ); document.write( "f(5) = \"25+-+30+%2B+10+\"\r
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\n" ); document.write( "\n" ); document.write( "f(5) = 5\r
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\n" ); document.write( "\n" ); document.write( "f(-2) = \"%28-2%29%5E2+-+7%2A%28-2%29+%2B+10+\"\r
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\n" ); document.write( "\n" ); document.write( "==> f(-2) = \"4++%2B+14++%2B+10+\"\r
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\n" ); document.write( "\n" ); document.write( "==> f(-2) = 28\r
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\n" ); document.write( "\n" ); document.write( "Hope you found the explanation useful.\r
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\n" ); document.write( "\n" ); document.write( "Praseena.\r
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