document.write( "Question 1043662: The perimeter of a rectangle is 80 feet. Express its area, A as a function of the length x of a side. \n" ); document.write( "
Algebra.Com's Answer #658810 by ikleyn(52890)\"\" \"About 
You can put this solution on YOUR website!
.
\n" ); document.write( "
\r\n" );
document.write( "Let L be the length of the rectangle, and W be the width.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Then L + W + L + W = P, perimeter, or  2*(L+W) = P,  or  L + W = \"P%2F2\" = \"80%2F2\" = 40 feet.\r\n" );
document.write( "\r\n" );
document.write( "Hence, W = 40 -L.\r\n" );
document.write( "\r\n" );
document.write( "The area of the rectangle is equal to \r\n" );
document.write( "\r\n" );
document.write( "A = L*W = L*(40-L) = \"40L+-+L%5E2\".\r\n" );
document.write( "\r\n" );
document.write( "So, A = \"40L+-+L%5E2\" expresses the area of the rectangle as the function of L.\r\n" );
document.write( "
\r
\n" ); document.write( "\n" ); document.write( "Solved.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "You can find many simple solved introductory problems on area of rectangle in the lesson \r
\n" ); document.write( "\n" ); document.write( "    - Problems on the area and the dimensions of a rectangle\r
\n" ); document.write( "\n" ); document.write( "in this site.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );