document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1043612>Question 1043612</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a 2-cup mixture consists of 1/3 flour and 2/3 cornmeal. if 1 cup of flour is added to make a 3-cup mixture, approximately what percent of the 3-cup mixture is flour? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #658798 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=658798\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a 2-cup mixture consists of 1/3 flour and 2/3 cornmeal. if 1 cup of flour is added to make a 3-cup mixture, approximately what percent of the 3-cup mixture is flour? <BR>\n" );
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document.write( "# of cups:: 3 cups<BR>\n" );
document.write( "# of cups of flour:: (1/3)(2) + 1 = 5/3 cup<BR>\n" );
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document.write( "Percent of flour = (5/3)/3 = 5/9 = 0.555.. = 55.6%<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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