document.write( "Question 90786: \n" ); document.write( "
Algebra.Com's Answer #65877 by malakumar_kos@yahoo.com(315)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( " One number is 5 times another. If the sum of their reciprocals is , find the two numbers. Define the variables you use, and remember to check your solutions\r
\n" ); document.write( "\n" ); document.write( " Let the variables be x & y
\n" ); document.write( " given one variable is 5 times the other , we get x = 5y.....eq'n (1)\r
\n" ); document.write( "\n" ); document.write( " sum of their reciprocals = 1/5, i.e, 1/x+1/y = 1/5........eq'n(2)\r
\n" ); document.write( "\n" ); document.write( " substitute for x in eq'n(2)\r
\n" ); document.write( "\n" ); document.write( " 1/5y+1/y = 1/5
\n" ); document.write( " (1+5)/5y = 1/5\r
\n" ); document.write( "\n" ); document.write( " 6/5y = 1/5\r
\n" ); document.write( "\n" ); document.write( " y = 6*5/5 = 6\r
\n" ); document.write( "\n" ); document.write( " substituting for y in Eq(1) we get x = 5*6 = 30\r
\n" ); document.write( "\n" ); document.write( " the solution for the variables is x =30 & y=6\r
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\n" ); document.write( "\n" ); document.write( "verification: x= 5y, 30 = 5*6, 30 = 30\r
\n" ); document.write( "\n" ); document.write( " 1/x+1/y = 1/5, 1/30+1/6 = 1/5, (1+5)/30 = 1/5, 6/30 = 1/5
\n" ); document.write( " 1/5 = 1/5
\n" ); document.write( " hence verified\r
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