document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1043597>Question 1043597</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve for 0 < theta < 2pi, giving your answers in terms of pi.\r<BR>\n" );
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document.write( "          1. Tan theta = - \"square root 3 over 3\"\r<BR>\n" );
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document.write( "          2. Cos^2 theta = 1 over 4 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #658742 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=658742\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Triangle that is 1-sqrt3-2 has a tangent that is 1/sqrt(3), and that is sqrt(3)/3<BR>\n" );
document.write( "That triangle is a 30-60-90 triangle, so the tangent that gives that value is 30 degrees or pi/6 radians.<BR>\n" );
document.write( "It also occurs when the sine and cosine are negative (tangent=sin/cos), and that would be at 210 degrees or 7pi/6 radians.<BR>\n" );
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document.write( "cos^2 theta=1/4<BR>\n" );
document.write( "cos theta= +/- 1/2<BR>\n" );
document.write( "That occurs at pi/6, pi/3, 2pi/3, and 5pi/3.  Notice that -1/2 is a solution, so there are twice as many instances.<BR>\n" );
document.write( "30-120-240-300 degrees. </SPAN>\n" );
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