document.write( "Question 1043584: I have worked out the quadratic equation for
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document.write( "x= -3q^2+150q, where q is quantity. The question asks what is the quantity is if x = 150? So I'm basically being asked what is q? I got:\r
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document.write( "q= 5(5 - radical 7) / 3 , q= 5(5 + radical 7) / 3
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document.write( "q=3.92375, q=12.74292.
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document.write( "But I don't know if that's the final answer to the question, or do I have to pick one of those two decimals? \n" );
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Algebra.Com's Answer #658728 by Edwin McCravy(20056)![]() ![]() You can put this solution on YOUR website! \r\n" ); document.write( "Apparently you made a mistake with the quadratic formula:\r\n" ); document.write( "\r\n" ); document.write( "x = -3q2+150q \r\n" ); document.write( "\r\n" ); document.write( "substitute 150 for x\r\n" ); document.write( "\r\n" ); document.write( "150 = -3q2+150q\r\n" ); document.write( "\r\n" ); document.write( "Get 0 on the right side:\r\n" ); document.write( "\r\n" ); document.write( "3q2-150q+150 = 0\r\n" ); document.write( "\r\n" ); document.write( "To make it easier to solve, divide every \r\n" ); document.write( "term on both sides by 3 -- since you can!:\r\n" ); document.write( "\r\n" ); document.write( "q2-50q+50 = 0\r\n" ); document.write( "\r\n" ); document.write( "a=1, b=-50, c=50\r\n" ); document.write( "\r\n" ); document.write( "\n" ); document.write( " |