document.write( "Question 1043539: Ref. Question 1043454:\r
\n" ); document.write( "\n" ); document.write( "Please list the operations you did after you substituted for y. I still don't understand. Sorry.
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Algebra.Com's Answer #658704 by MathTherapy(10555)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "Ref. Question 1043454:\r
\n" ); document.write( "\n" ); document.write( "Please list the operations you did after you substituted for y. I still don't understand. Sorry.
\n" ); document.write( "
You seem to want to use 2 equations to solve for x, in terms of 3 other variables. Why didn't you say so when question 1043447 was submitted? \r
\n" ); document.write( "\n" ); document.write( "Question 1043447: If a is added to the difference of 2 quantities, the sum is b, and if the larger is divided by the smaller, the quotient is c. Determine quantities.
\n" ); document.write( "Let x = larger
\n" ); document.write( "Let y = smaller
\n" ); document.write( "My attempt:
\n" ); document.write( "x - y + a = b
\n" ); document.write( "x / y = c
\n" ); document.write( "How do I proceed ? \r
\n" ); document.write( "\n" ); document.write( "Apparently, you want to solve for x using the following equations:
\n" ); document.write( "x - y + a = b______y = x + a - b ------ eq (i)
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\n" ); document.write( "Since y = x + a - b, and \"y+=+x%2Fc\", it follows that: \"x+%2B+a+-+b+=+x%2Fc\"
\n" ); document.write( "cx + ac - bc = x ------- Multiplying by LCD, c
\n" ); document.write( "x - cx = ac - bc
\n" ); document.write( "x(1 - c) = ac - bc
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