document.write( "Question 1043517: how many different four digit numbers can be formed by rearranging the digits of 2010? \n" ); document.write( "
Algebra.Com's Answer #658664 by ikleyn(52864)\"\" \"About 
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\n" ); document.write( "how many different four digit numbers can be formed by rearranging the digits of 2010?
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document.write( "Everything that does not start with \"0\" in the most left position.\r\n" );
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document.write( "It gives you 2*3*2*1 = 12 options.\r\n" );
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document.write( "And having two indistinguishable digits \"0\" forces you to divide 12 by 2! = 2.\r\n" );
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document.write( "In total, there are  \"12%2F2\" = 6 options.  6 numbers.\r\n" );
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document.write( "Answer. 6 numbers.\r\n" );
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document.write( "They are\r\n" );
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document.write( "2100  1200\r\n" );
document.write( "2010  1020\r\n" );
document.write( "2001  1002\r\n" );
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