document.write( "Question 1043490: If a^2+b^2=7ab prove that 2 log(a-b)=log 5+log a+log b \n" ); document.write( "
Algebra.Com's Answer #658655 by ikleyn(52816)\"\" \"About 
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\n" ); document.write( "If a^2 + b^2=7 ab, then prove that 2 log (a-b)=log 5+log a+log b
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document.write( "If \"a%5E2+%2B+b%5E2\" = \"7ab\", then\r\n" );
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document.write( "\"a%5E2+-+2ab+%2B+b%5E2\" = \"7ab+-+2ab\"    (after adding 2ab to both side)\r\n" );
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document.write( "\"%28a+-+b%29%5E2\" = \"5ab\".\r\n" );
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document.write( "Now take the logarithm of both sides (assuming a > b > 0, which MUST be pointed in the condition, but mistakenly missed).\r\n" );
document.write( "You will get\r\n" );
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document.write( "2*log(a-b) = log(5) + log(a) + log(b).   QED.\r\n" );
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