document.write( "Question 1043454: Ref. Question 1043447:\r
\n" ); document.write( "\n" ); document.write( "I am not totally clear on the steps to solve for x. Thanks.
\n" ); document.write( "

Algebra.Com's Answer #658611 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
Question # 10434447: If a is added to the difference of 2 quantities, the sum is b, and if the larger is divided by the smaller, the quotient is c. Determine quantities. \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"system%28a%2Bx-y=b%2Cx%2Fy=c%29\" and you want to solve for x and y.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x%2Fy=c\"
\n" ); document.write( "\"x=cy\"
\n" ); document.write( "-
\n" ); document.write( "substitute for x into the \"b\" equation and first solve for y.
\n" ); document.write( "\"a%2Bcy-y=b\"
\n" ); document.write( "\"cy-y=b-a\"
\n" ); document.write( "\"y%28c-1%29=b-a\"
\n" ); document.write( "\"highlight%28y=%28b-a%29%2F%28c-1%29%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "You have either of two choices to solve for x. You could use now found y and substitute into either equation, or you could take the ratio equation from the description and solve it for y and then substitute into the \"b\" equation. I will do this second way.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x%2Fy=c\"
\n" ); document.write( "\"y%2Fx=1%2Fc\"
\n" ); document.write( "\"y=x%2Fc\"
\n" ); document.write( "-
\n" ); document.write( "\"a%2Bx-y=b\"
\n" ); document.write( "\"x-y=b-a\"
\n" ); document.write( "\"x-x%2Fc=b-a\"--------the substitution for y
\n" ); document.write( "\"x%281-1%2Fc%29=b-a\"
\n" ); document.write( "\"x%28c%2Fc-1%2Fc%29=b-a\"
\n" ); document.write( "\"x%28c-1%29%2Fc=b-a\"
\n" ); document.write( "\"x=%28b-a%29%28c%2F%28c-1%29%29\"
\n" ); document.write( "\"highlight%28x=c%28b-a%29%2F%28c-1%29%29\"-----solved for x
\n" ); document.write( "
\n" );