document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1043447>Question 1043447</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If a is added to the difference of 2 quantities, the sum is b, and if the larger is divided by the smaller, the quotient is c.  Determine quantities.\r<BR>\n" );
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document.write( "Let x = larger<BR>\n" );
document.write( "Let y = smaller\r<BR>\n" );
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document.write( "My attempt:\r<BR>\n" );
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document.write( "x - y + a = b\r<BR>\n" );
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document.write( "x / y = c\r<BR>\n" );
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document.write( "How do I proceed ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #658587 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=658587\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x=cy from the second<BR>\n" );
document.write( "substitute into the first<BR>\n" );
document.write( "cy-y+a=b<BR>\n" );
document.write( "y(c-1)=b-a, moving the a<BR>\n" );
document.write( "y=(b-a)/(c-1), dividing both sides by (c-1)<BR>\n" );
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document.write( "substitute that into the first<BR>\n" );
document.write( "x-(b-a)/(c-1)=b-a<BR>\n" );
document.write( "add the second term to both sides<BR>\n" );
document.write( "x=(b-a)/(c-1)+(b-a)<BR>\n" );
document.write( "put it over a common denominator, multiplying (b-a)(c-1) to get bc-b-ac+a<BR>\n" );
document.write( "x=[1/(c-1)]{b-a+bc-b-ac+a}; the a and b cancel, and x=(bc-ac)/(c-1)<BR>\n" );
document.write( "x=c(b-a)/(c-1)<BR>\n" );
document.write( "Notice that x is cy<BR>\n" );
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document.write( "Let x=10<BR>\n" );
document.write( "y=5<BR>\n" );
document.write( "a=3<BR>\n" );
document.write( "10-5+3=8, so b=8<BR>\n" );
document.write( "10/5=2, so c=2<BR>\n" );
document.write( "See if the above formulae work<BR>\n" );
document.write( "For y=(b-a)/(c-1), we get (8-3)/(2-1), and that is 5.<BR>\n" );
document.write( "for x=c(b-a)/(c-1), we get 2(8-3)/(2-1)=10. </SPAN>\n" );
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