document.write( "Question 1043438: The table shows the results of a survey in which separate samples of 400 adults each from the East, South, Midwest, and West were asked if traffic congestion is a serious problem in their community. Complete part (a)\r
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document.write( "East 36%
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document.write( "South 33%
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document.write( "Midwest 25%
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document.write( "West 55%\r
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document.write( "(a) Construct a 95% confidence interval for the proportion of adults from the East who say traffic congestion is a serious problem.\r
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document.write( "The 95% confidence interval for the proportion of adults from the East who say traffic congestion is a serious problem is? Round to three decimal places as needed. \n" );
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Algebra.Com's Answer #658572 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! CI interval for 95% is z*sqrt{ (p)*(1-p)/n} \n" ); document.write( "That is 1.96*sqrt {(0.36)(0.64)/400} \n" ); document.write( "'That is 1.96 sqrt (0.000576)=1.96*0.024=0.047 \n" ); document.write( "The interval is 0.36+/-0.047, or (0.313,0.407) \n" ); document.write( " |