document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1043412>Question 1043412</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the supplement of an angle is 2/3 of itself then determine the angle </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #658563 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=658563\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x is the angle<BR>\n" );
document.write( "supplementary angles add to 180<BR>\n" );
document.write( "2/3 of the angle is (2/3)x<BR>\n" );
document.write( "Therefore x+(2/3)x=(5/3)x<BR>\n" );
document.write( "That equals 180<BR>\n" );
document.write( "multiply both sides by the reciprocal of (5/3)<BR>\n" );
document.write( "the left side becomes x, the right side becomes 180*(3/5)=108 degrees.<BR>\n" );
document.write( "The angle is 108 degrees<BR>\n" );
document.write( "(2/3) of it is 72 degrees ANSWER<BR>\n" );
document.write( "They add to 180 degrees </SPAN>\n" );
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