document.write( "Question 1043391: Find the other factors of P(x)=x^5-x^4-20x^3+20x^2+64x-64 if you are given that x-4 and x+4 are factors of P(x) \n" ); document.write( "

Algebra.Com's Answer #658538 by josgarithmetic(39620) $\"\"$ $\"About$

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Try synthetic division to break P one factor at a time. You could try instead divisor x^2-16, but using synthetic division with first x-4 and then x+4 divisors could be easier. You still then need to handle the cubic result, whichever way you choose.\r
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document.write( "4   |   1   -1   -20   20   64    -64\r\n" );
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document.write( "    |       4    12    32   104   672\r\n" );
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document.write( "       1    3     8    52   168    608\r\n" );
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\n" ); document.write( "\n" ); document.write( "NO. x-4 AND x+4 ARE NOT BOTH FACTORS OF P(x). \n" ); document.write( "

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