document.write( "Question 1043317: a box contains 18 smartphones. 4 are defective. 3 smartphones randomly selected and tested. what is the probability that first two are defective and the third is working if the first and second are not replaced after being tested? \n" ); document.write( "
Algebra.Com's Answer #658514 by Boreal(15235) You can put this solution on YOUR website! probability first two are defective is (4/18)(3/17)=12/306 \n" ); document.write( "probability third is working is (14/16) \n" ); document.write( "The total probability is (12/306)(14/16)=0.0343 \n" ); document.write( " |