document.write( "Question 1043320: A number consists of two digits, the digits in the ten’s place exceeds that in the unit’s place by 5 and if 5 times the sum of the digits be subtracted from the number, the digits will be reversed. Find the number. \n" ); document.write( "
Algebra.Com's Answer #658477 by ankor@dixie-net.com(22740)\"\" \"About 
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let a = the 10's digit
\n" ); document.write( "let b = the units
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\n" ); document.write( "Write an equation for each statement
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\n" ); document.write( "A number consists of two digits, the digits in the ten’s place exceeds that in the unit’s place by 5
\n" ); document.write( "a = b + 5
\n" ); document.write( " and if 5 times the sum of the digits be subtracted from the number, the digits will be reversed.
\n" ); document.write( "10a + b - 5(a+b) = 10b + a
\n" ); document.write( "10a + b - 5a - 5b = 10b + a
\n" ); document.write( "combine a's on the left, b's on the right
\n" ); document.write( "10a - 5a - a = 10b - b + 5b
\n" ); document.write( "4a = 14b
\n" ); document.write( "simplify, divide by 2
\n" ); document.write( "2a = 7b
\n" ); document.write( "from the 1st statement, replace a with (b+5)
\n" ); document.write( "2(b+5) = 7b
\n" ); document.write( "2b + 10 = 7b
\n" ); document.write( "10 = 7b - 2b
\n" ); document.write( "10 = 5b
\n" ); document.write( "b = 10/5
\n" ); document.write( "b = 2
\n" ); document.write( "then
\n" ); document.write( "a = 2 + 5
\n" ); document.write( "a = 7
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\n" ); document.write( "72 is our number
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\n" ); document.write( "Check solution in the 2nd statement
\n" ); document.write( "72 - 5(7+2) = 27
\n" ); document.write( "72 - 45 = 27\r
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