document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1043326>Question 1043326</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The equation of a curve is y=tan(x+1). Find, to two decimal places, the gradient of the normal to the curve at the point where x=0. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #658468 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=658468\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The equation of a curve is y=tan(x+1). Find, to two decimal places, the gradient of the normal to the curve at the point where x=0.<BR>\n" );
document.write( "--------<BR>\n" );
document.write( "y = tan(x+1)<BR>\n" );
document.write( "y' = sec^2(x+1)  -  1st derivative<BR>\n" );
document.write( "y'(0) = sec^2(1) = 3.4255<BR>\n" );
document.write( "--> -1/3.4255 =~ -0.29 </SPAN>\n" );
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