document.write( "Question 1043288: Solve each equation by either substitution or addition method.
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document.write( " x2 + 4y2 = 20
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document.write( "x + 2y = 6
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Algebra.Com's Answer #658423 by stanbon(75887) ![]() You can put this solution on YOUR website! Solve each equation by either substitution or addition method. \n" ); document.write( "x^2 + 4y^2 = 20 \n" ); document.write( "x + 2y = 6 \n" ); document.write( "----------- \n" ); document.write( "x = 6-2y \n" ); document.write( "----- \n" ); document.write( "Substitute for \"x\" and solve for \"y\":: \n" ); document.write( "(6-2y)^2 + 4y^2 = 20 \n" ); document.write( "-------- \n" ); document.write( "36 - 24y + 4y^2 + 4y^2 = 20 \n" ); document.write( "-------- \n" ); document.write( "8y^2 - 24y +16 = 0 \n" ); document.write( "-------- \n" ); document.write( "y^2 - 3y + 2 = 0 \n" ); document.write( "-------- \n" ); document.write( "(y-1)(y-2) = 0 \n" ); document.write( "------- \n" ); document.write( "Solve for \"x\" \n" ); document.write( "If y = 1, x = 6-2y = 4 \n" ); document.write( "If y = 2, x = 6-2y = 2 \n" ); document.write( "---------------------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "---------------------- \n" ); document.write( " \n" ); document.write( " |