document.write( "Question 1043288: Solve each equation by either substitution or addition method.
\n" ); document.write( " x2 + 4y2 = 20
\n" ); document.write( "x + 2y = 6
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Algebra.Com's Answer #658423 by stanbon(75887)\"\" \"About 
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Solve each equation by either substitution or addition method.
\n" ); document.write( "x^2 + 4y^2 = 20
\n" ); document.write( "x + 2y = 6
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\n" ); document.write( "x = 6-2y
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\n" ); document.write( "Substitute for \"x\" and solve for \"y\"::
\n" ); document.write( "(6-2y)^2 + 4y^2 = 20
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\n" ); document.write( "36 - 24y + 4y^2 + 4y^2 = 20
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\n" ); document.write( "8y^2 - 24y +16 = 0
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\n" ); document.write( "y^2 - 3y + 2 = 0
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\n" ); document.write( "(y-1)(y-2) = 0
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\n" ); document.write( "Solve for \"x\"
\n" ); document.write( "If y = 1, x = 6-2y = 4
\n" ); document.write( "If y = 2, x = 6-2y = 2
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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