document.write( "Question 1043253: The numerator of a fraction is 7 less than the denominator. If one and one third is added to it, the fraction obtained is 14/9. Find the original fraction. \n" ); document.write( "
Algebra.Com's Answer #658386 by LinnW(1048)![]() ![]() You can put this solution on YOUR website! Let n = numerator \n" ); document.write( "Let d = denominator \n" ); document.write( "d = n-7 \n" ); document.write( "fraction is \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "add -4/3 to each side \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "do cross products \n" ); document.write( "9n = 2(n-7) \n" ); document.write( "9n = 2n -14 \n" ); document.write( "add -2n to each side \n" ); document.write( "7n = -14 \n" ); document.write( "divide each side by 7 \n" ); document.write( "n = -2 \n" ); document.write( "So the original fraction is \n" ); document.write( " \n" ); document.write( " |