document.write( "Question 1043253: The numerator of a fraction is 7 less than the denominator. If one and one third is added to it, the fraction obtained is 14/9. Find the original fraction. \n" ); document.write( "
Algebra.Com's Answer #658386 by LinnW(1048)\"\" \"About 
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Let n = numerator
\n" ); document.write( "Let d = denominator
\n" ); document.write( "d = n-7
\n" ); document.write( "fraction is \"n%2F%28n-7%29\"
\n" ); document.write( "\"n%2F%28n-7%29%2B%281%2B1%2F3%29=14%2F9\"
\n" ); document.write( "\"n%2F%28n-7%29%2B%284%2F3%29=14%2F9\"
\n" ); document.write( "add -4/3 to each side
\n" ); document.write( "\"n%2F%28n-7%29=%2814%2F9%29-%284%2F3%29\"
\n" ); document.write( "\"n%2F%28n-7%29=%2814%2F9%29-%2812%2F9%29\"
\n" ); document.write( "\"n%2F%28n-7%29=%282%2F9%29\"
\n" ); document.write( "do cross products
\n" ); document.write( "9n = 2(n-7)
\n" ); document.write( "9n = 2n -14
\n" ); document.write( "add -2n to each side
\n" ); document.write( "7n = -14
\n" ); document.write( "divide each side by 7
\n" ); document.write( "n = -2
\n" ); document.write( "So the original fraction is \"%28-2%29%2F%28-9%29\"
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