document.write( "Question 1043253: The numerator of a fraction is 7 less than the denominator. If one and one third is added to it, the fraction obtained is 14/9. Find the original fraction. \n" ); document.write( "
Algebra.Com's Answer #658381 by Cromlix(4381)![]() ![]() You can put this solution on YOUR website! Hi there, \n" ); document.write( "The numerator of a fraction is 7 less than the denominator. \n" ); document.write( "Make denominator = x \n" ); document.write( "(x - 7)/x \n" ); document.write( "If one and one third is added to it, the fraction obtained is 14/9. \n" ); document.write( "(x - 7)/x + 4/3 = 14/9 \n" ); document.write( "Take lowest common denominator = 27x \n" ); document.write( "[27(x - 7) + 9x(4) = 3x(14)] \n" ); document.write( "[27x - 189 + 36x = 42x] \n" ); document.write( "Collect like terms \n" ); document.write( "27x + 36x - 42x = 189 \n" ); document.write( "21x = 189 \n" ); document.write( "x = 9 \n" ); document.write( "Original fraction = \n" ); document.write( "(x - 7)/x \n" ); document.write( "(9 -7)/9 \n" ); document.write( "2/9. \n" ); document.write( "Proof: \n" ); document.write( "2/9 + 4/3 = 14/9 \n" ); document.write( "Hope this helps :-) \n" ); document.write( " |