document.write( "Question 1043253: The numerator of a fraction is 7 less than the denominator. If one and one third is added to it, the fraction obtained is 14/9. Find the original fraction. \n" ); document.write( "
Algebra.Com's Answer #658381 by Cromlix(4381)\"\" \"About 
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Hi there,
\n" ); document.write( "The numerator of a fraction is 7 less than the denominator.
\n" ); document.write( "Make denominator = x
\n" ); document.write( "(x - 7)/x
\n" ); document.write( "If one and one third is added to it, the fraction obtained is 14/9.
\n" ); document.write( "(x - 7)/x + 4/3 = 14/9
\n" ); document.write( "Take lowest common denominator = 27x
\n" ); document.write( "[27(x - 7) + 9x(4) = 3x(14)]
\n" ); document.write( "[27x - 189 + 36x = 42x]
\n" ); document.write( "Collect like terms
\n" ); document.write( "27x + 36x - 42x = 189
\n" ); document.write( "21x = 189
\n" ); document.write( "x = 9
\n" ); document.write( "Original fraction =
\n" ); document.write( "(x - 7)/x
\n" ); document.write( "(9 -7)/9
\n" ); document.write( "2/9.
\n" ); document.write( "Proof:
\n" ); document.write( "2/9 + 4/3 = 14/9
\n" ); document.write( "Hope this helps :-)
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