document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=90704>Question 90704</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the distance between (6, –2) and (–6, 3).  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #65836 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=65836\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> THE X SIDE IS (6+6)=12<BR>\n" );
document.write( "THE Y SIDE IS (3+2)=5<BR>\n" );
document.write( "SO THE DISTANCE IS THE HYPOTENUSE THUS<BR>\n" );
document.write( "12^2+5^2=H^2<BR>\n" );
document.write( "144+25=H^2<BR>\n" );
document.write( "169=H^2<BR>\n" );
document.write( "H=SQRT169<BR>\n" );
document.write( "H=13 IS THE HYPOTENUSE & THE DISTANCE BETWEEN THESE POINTS. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );