document.write( "Question 90696This question is from textbook Beginning Al
\n" ); document.write( ": Solve by completing the square: 4x^2 + 2x - 3 = 0
\n" ); document.write( "4x^2 + 2x = 3
\n" ); document.write( "x^2 + 2/4x = 3/4
\n" ); document.write( "Square one-half of the of the x-coefficient and then add it to both sides
\n" ); document.write( "1/2 of 2/4 = 1/4^2 = 1/16
\n" ); document.write( "x^2 + 2/4x + 1/16 = 3/4 + 1/16
\n" ); document.write( "(x-1/4)^2 = 13/16
\n" ); document.write( "x - 1/4 = +/- radical 13 over radical 16
\n" ); document.write( "x - 1/4 = +/- radical 13 over 4
\n" ); document.write( "x = 1/4 +/- radical 13 over 4
\n" ); document.write( "x = 1 +/- radical 13 over 4\r
\n" ); document.write( "\n" ); document.write( "Again, any feedback would be appreicated! \n" ); document.write( "

Algebra.Com's Answer #65828 by vertciel(183) $\"\"$ $\"About$

You can put this solution on YOUR website!
Hello there,\r
\n" ); document.write( "\n" ); document.write( "I couldn't understand your answer but if you got the following two x values, then your answer is right.\r
\n" ); document.write( "\n" ); document.write( "x ≈ 0.6514\r
\n" ); document.write( "\n" ); document.write( "x ≈ -1.1514\r
\n" ); document.write( "\n" ); document.write( "I solved the equation with my graphing calculator so I don't have any steps. If you didn't get these roots and you want more help, please write back! \n" ); document.write( "

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