document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1043135>Question 1043135</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how long will it take for &#8203;$4300 to grow to &#8203;$28600 at an interest rate of 3% if the interest is compounded&#8203; continuously? Round the number of years to the nearest hundredth. thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #658249 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=658249\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  how long will it take for &#8203;$4300 to grow to &#8203;$28600 at an interest rate of 3% if the interest is compounded&#8203; continuously? Round the number of years to the nearest hundredth.<BR>\n" );
document.write( "A(t) = P*e^(r*t)<BR>\n" );
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document.write( "28600 = 4300*e^(0.03*t)<BR>\n" );
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document.write( "e^(0.03t) = 6.6512<BR>\n" );
document.write( "0.03t = ln(6.6512)<BR>\n" );
document.write( "t = 1.8948/0.03<BR>\n" );
document.write( "t = 63.16 years<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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document.write( " </SPAN>\n" );
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