document.write( "Question 1042771: A salesperson has a policy of calling upon a customer a second time if she does not make the sale on the first call, and trying a third time, and last time if she fails on the first two calls. She has a probability of a sale on the first call of 0.3. If she fails on the first call, the probability of a sale on the second call is 0.2. If the first two calls are unsuccessful, her probability of success on the third call is only 0.1.
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document.write( "how i want do tree diagram for this question? \n" );
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Algebra.Com's Answer #658184 by mathmate(429) You can put this solution on YOUR website! Question: \n" ); document.write( "A salesperson has a policy of calling upon a customer a second time if she does not make the sale on the first call, and trying a third time, and last time if she fails on the first two calls. She has a probability of a sale on the first call of 0.3. If she fails on the first call, the probability of a sale on the second call is 0.2. If the first two calls are unsuccessful, her probability of success on the third call is only 0.1. \n" ); document.write( "how i want do tree diagram for this question? \n" ); document.write( " \n" ); document.write( "Answer: \n" ); document.write( "The tree diagram is shown below. \n" ); document.write( "It is as important to understand how to interpret a tree-diagram as to draw it. \n" ); document.write( "The probability of failure is the product of probabilities of all three steps, namely \n" ); document.write( "P(failure)=0.7*0.8*0.9=0.504 \n" ); document.write( "The probability of success, however, is the sum of three possible cases, depending on the number of calls made. \n" ); document.write( "P(success on first call)=0.3=0.300 \n" ); document.write( "P(success on second call)=0.7*0.2=0.140 \n" ); document.write( "P(success on third call)=0.7*0.8*0.1=0.056 \n" ); document.write( "So total probability of success \n" ); document.write( "P(success)=0.300+0.140+0.056=0.496 \n" ); document.write( "which is complementary to P(failure), or \n" ); document.write( "P(success)+P(failure)= 1.000 \n" ); document.write( "is a good check for the ansewr. \n" ); document.write( " |