document.write( "Question 1043022: Solve for x on the interval [0,2pi]. \r
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\n" ); document.write( "\n" ); document.write( "cos^2(x)+3cos(x)+2=0\r
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Algebra.Com's Answer #658099 by ikleyn(52884)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "\"cos%5E2%28x%29%2B3cos%28x%29%2B2\" = \"0\"\r\n" );
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document.write( "Factor left side\r\n" );
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document.write( "(cos(x) + 1)*(cos(x) + 2) = 0.\r\n" );
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document.write( "Then the original equation deploys in two separate independent equations\r\n" );
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document.write( "1.  cos(x) + 1 = 0  --->  cos(x) = -1  --->  x = \"3pi%2F2\",  and\r\n" );
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document.write( "2.  cos(x) + 2 = 0  --->  cos(x) = -2,  which has no solutions.\r\n" );
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document.write( "Answer.  x = \"3pi%2F2\".\r\n" );
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\n" ); document.write( "\n" ); document.write( "They teach you by examples on how to solve similar and other trigonometric equations.\r
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