document.write( "Question 1042959: 5 years ago a man was 7 times as old as his son. 5 years hence , the father will be three times as old as his son. Find their present ages. \n" ); document.write( "
Algebra.Com's Answer #658029 by stanbon(75887)\"\" \"About 
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5 years ago a man was 7 times as old as his son. 5 years hence , the father will be three times as old as his son. Find their present ages.
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\n" ); document.write( "f-5 = 7(s-5)
\n" ); document.write( "f+5 = 3(s+5)
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\n" ); document.write( "Simplify::
\n" ); document.write( "f - 7s = -30
\n" ); document.write( "f - 3s = 10
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\n" ); document.write( "Subtract and solve for \"s\":
\n" ); document.write( "4s = 40
\n" ); document.write( "son's age = 10 yrs
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\n" ); document.write( "Solve for \"f\":
\n" ); document.write( "f - 5 = 7(s-5)
\n" ); document.write( "f - 5 = 7(10-5)
\n" ); document.write( "f = 7*5+5 = 40 years (father's age)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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