document.write( "Question 1042959: 5 years ago a man was 7 times as old as his son. 5 years hence , the father will be three times as old as his son. Find their present ages. \n" ); document.write( "
Algebra.Com's Answer #658029 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! 5 years ago a man was 7 times as old as his son. 5 years hence , the father will be three times as old as his son. Find their present ages. \n" ); document.write( "----- \n" ); document.write( "f-5 = 7(s-5) \n" ); document.write( "f+5 = 3(s+5) \n" ); document.write( "------------------- \n" ); document.write( "Simplify:: \n" ); document.write( "f - 7s = -30 \n" ); document.write( "f - 3s = 10 \n" ); document.write( "------ \n" ); document.write( "Subtract and solve for \"s\": \n" ); document.write( "4s = 40 \n" ); document.write( "son's age = 10 yrs \n" ); document.write( "-------------- \n" ); document.write( "Solve for \"f\": \n" ); document.write( "f - 5 = 7(s-5) \n" ); document.write( "f - 5 = 7(10-5) \n" ); document.write( "f = 7*5+5 = 40 years (father's age) \n" ); document.write( "------------------ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |