document.write( "Question 1042781: Given the rectangle ABCD, with tan angle x= 3/4 and tan angle y= 1/6, the area of the shaded region is what fraction of the area of the rectangle?
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Algebra.Com's Answer #658022 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "Since the actual size of the rectangle is arbitrary, we can use the fact that the tangent of x is 3/4 to assign the value 4 to the measure of the side of the rectangle that is adjacent to angle x, and the value 3 to the measure of the side opposite angle x. The other long side of the rectangle must also be 4, and since 4 is 2/3 of 6, assign 2/3 (2/3 times 1) to the segment that is opposite angle y.\r
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\n" ); document.write( "\n" ); document.write( "Then, relatively speaking, the area of the entire rectangle is 12 square units, the area of the triangle containing angle x is 6 square units, and the area of the triangle containing angle y is 4/3 square units. The sum of the areas of the two triangles is then 22/3 and 22/3 divided by 12 is 11/18.\r
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\n" ); document.write( "\n" ); document.write( "Then the shaded area is 1 minus 11/18. 7/18\r
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\n" ); document.write( "\n" ); document.write( "John
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\n" ); document.write( "My calculator said it, I believe it, that settles it
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