document.write( "Question 1042942: Determine, without graphing, whether the given quadratic function has a maximum value or a minimum value and then find that value.\r
\n" ); document.write( "\n" ); document.write( "f(x) = x^2 - 2x - 5
\n" ); document.write( " a. maximum; 1
\n" ); document.write( " b. minimum; 1
\n" ); document.write( " c. maximum; - 6
\n" ); document.write( " d. minimum; - 6 \n" ); document.write( "

Algebra.Com's Answer #658016 by ikleyn(52776) $\"\"$ $\"About$

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document.write( "1. It has the minimum.\r\n" );
document.write( "   Since it is a parabola opened up.\r\n" );
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document.write( "   It is the parabola opened up, because its leading coefficient is positive.\r\n" );
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document.write( "2.  The minimum is at x = 1.   (Option b)\r\n" );
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document.write( "    Because for the general quadratic function y = ax^2 + bx + c the min/max is at x = .  \r\n" );
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document.write( "    It is  = 1 in your case.\r\n" );
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document.write( "3.  To get the value of the minimum, substitute this x=1 into the formula for your quadratic function. You will get\r\n" );
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document.write( "    f(x) =  = 1 - 2 - 5 = -6.\r\n" );
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\n" ); document.write( "\n" ); document.write( "See the lesson Who is who in quadratic equations in this site.\r
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