document.write( "Question 1042849: Please help me solve this problem..\r
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document.write( "A sample of 32 observations is selected from a normal population. The sample mean is 32, and the population standard deviation is 6. Conduct the following test of hypothesis using the 0.05 significance level.
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document.write( "H0 : μ ≤ 29
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document.write( "H1 : μ > 29 \r
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document.write( "a. Is this a one- or two-tailed test?
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document.write( " \"One-tailed\"-the alternate hypothesis is greater than direction.
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document.write( " \"Two-tailed\"-the alternate hypothesis is different from direction.
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document.write( "b. What is the decision rule? (Round your answer to 3 decimal places.) \r
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document.write( " (Click to select)RejectDo not reject H0, when z > \r
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document.write( "c. What is the value of the test statistic? (Round your answer to 2 decimal places.) \r
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document.write( " Value of the test statistic \r
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document.write( "d. What is your decision regarding H0?
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document.write( " Reject
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document.write( " Do not reject
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document.write( "There is (Click to select)insufficientsufficient evidence to conclude that the population mean is greater than 29. \r
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document.write( "e. What is the p-value? (Round your answer to 4 decimal places.) \r
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document.write( " p-value
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Algebra.Com's Answer #657986 by rothauserc(4718)![]() ![]() You can put this solution on YOUR website! a) this is a one-tailed test since H1 does not contain = sign \n" ); document.write( ": \n" ); document.write( "b) At a 5% significance level, the critical value for a one tailed test is found from the table of z-scores to be 1.645 \n" ); document.write( "Reject when z > 1.645 \n" ); document.write( ": \n" ); document.write( "c) standard error of the mean (SE) = population standard deviation / square root(sample size) \n" ); document.write( "SE = 6 / square root(32) approx 1.061 \n" ); document.write( "z value = (32 - 29) / 1.061 approx 2.83 \n" ); document.write( ": \n" ); document.write( "d) reject H0 since 2.83 > 1.645 \n" ); document.write( ": \n" ); document.write( "e) a z-score of 2.83 has a p-value of 0.0026 \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( " |