document.write( "Question 1042905: A steamer goes downstream from one point to another in 9 hours. It covers the same distance upstream in 10 hours. If the speed of the stream be 1 km/hr , find the speed of the steamer in still water and the distance between the ports . \n" ); document.write( "
Algebra.Com's Answer #657954 by ikleyn(52788)\"\" \"About 
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\n" ); document.write( "A steamer goes downstream from one point to another in 9 hours. It covers the same distance upstream in 10 hours.
\n" ); document.write( "If the speed of the stream be 1 km/hr , find the speed of the steamer in still water and the distance between the ports .
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document.write( "Let D be the distance between the ports (in kilometers), and\r\n" );
document.write( "let u be the streamer speed in still water.\r\n" );
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document.write( "Then you have these two equations\r\n" );
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document.write( "\"D%2F9\" = u + 1,   (1)    ( speed equation for moving downstream )\r\n" );
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document.write( "\"D%2F10\" = u - 1,  (2)    ( speed equation for moving upstream )\r\n" );
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document.write( "Distract equation (2) from (1) (both sides). You will get\r\n" );
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document.write( "\"D%2F9+-+D%2F10\" = 2  --->  \"%2810D%29%2F90+-+%289D%29%2F90\" = 2  --->  \"D%2F90\" = 2  --->  D = 2*90 = 180.\r\n" );
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document.write( "Thus we found the distance. It is 180 kilometers.\r\n" );
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document.write( "Now from (1),\r\n" );
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document.write( "\"180%2F9\" = u + 1  ---> 20 = u + 1  --->  u = 20-1 = 19.\r\n" );
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document.write( "The treamer speed in still water is 19 \"km%2Fh\".\r\n" );
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