document.write( "Question 1042896: Solve for x if log_4 x-1+log_4 (x-1)=0 \n" ); document.write( "

Algebra.Com's Answer #657943 by Fombitz(32388) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"log%284%2C%28x-1%29%29%2Blog%284%2C%28x-1%29%29=0\"$
\n" ); document.write( " $\"2%2Alog%284%2C%28x-1%29%29=0\"$
\n" ); document.write( " $\"log%284%2C%28x-1%29%5E2%29=0\"$
\n" ); document.write( " $\"%28x-1%29%5E2=1\"$
\n" ); document.write( " $\"x-1=0+%2B-+1\"$
\n" ); document.write( " $\"x=2\"$ and $\"x=0\"$
\n" ); document.write( "However when $\"x=0\"$ you get a negative log argument which is not allowed.
\n" ); document.write( "So,
\n" ); document.write( " $\"x=2\"$ is the only solution.\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

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