document.write( "Question 1042819: Please help me solve this problem:
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document.write( "Which of the following equations have extraneous solutions?
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document.write( "a)(1/(x-1))+(x/5)=(x/(x-1))
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document.write( "b)(x+3)/(x+5)=(2x+8)/(x+5)
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document.write( "c)x-(2/x)=-1
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document.write( "d)3/(x+7)=5/(x-2) \n" );
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Algebra.Com's Answer #657875 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Which of the following equations have extraneous solutions? \n" ); document.write( "a)(1/(x-1))+(x/5)=(x/(x-1)) \n" ); document.write( "Multiply thru by 5(x-1) to get: \n" ); document.write( "5 + x(x-1) = 5x \n" ); document.write( "5 + x^2 - x = 5x \n" ); document.write( "x^2 - 6x + 5 = 0 \n" ); document.write( "(x-5)(x-1) = 0 \n" ); document.write( "x = 1 is extraneous because x-1 is in the denominator: \n" ); document.write( "------------------------------------------ \n" ); document.write( "b)(x+3)/(x+5)=(2x+8)/(x+5) \n" ); document.write( "x+3 = 2x+8 \n" ); document.write( "x = -5 is extraneous because x+5 is in the denominator \n" ); document.write( "---------------------- \n" ); document.write( "c)x-(2/x)=-1 \n" ); document.write( "x^2 - 2 = -x \n" ); document.write( "x^2 + x - 2 = 0 \n" ); document.write( "(x+2)(x-1) = 0 \n" ); document.write( "x = -2 or x = 1 \n" ); document.write( "No extraneous zeroes \n" ); document.write( "------------------------- \n" ); document.write( "d)3/(x+7)=5/(x-2) \n" ); document.write( "3x-6 = 5x+35 \n" ); document.write( "2x = -41 \n" ); document.write( "x = -20.5 \n" ); document.write( "No extraneous \n" ); document.write( "-------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "------------- \n" ); document.write( " |