Algebra.Com's Answer #657840 by stanbon(75887)![\"\"](\"/images/stars/stars-13.gif\")  
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The cost of a can of Coca-Cola on January 1, 1960 , was 10 cents. The function C(t)=0.10e^(0.0576t) gives the cost of a can of Coca-Cola, C(t), t years after that.\r
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document.write( "a.) How much does a can of Coca Cola cost in 1975 (round to nearest penny)?
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document.write( "# of years 60 to 75 = 15
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document.write( "C(15) = 0.10*e^(0.0576*15) = 0.10*2.3726 = 0.237 = 24 cents if rounded up
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document.write( "b.) In what year will a can of Coca-Cola cost $1.00 (round to nearest whole year).
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document.write( "Solve for \"t\"
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document.write( "1 = 0.10*e^(0.0576t)
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document.write( "e^(0.0576t) = 10
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document.write( "Take the natural log of both sides to get:
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document.write( "0.0576t = 2.3026
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document.write( "t = 40 if rounded up
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document.write( "Ans: 1960 + 40 = year 2000
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document.write( "c.) How much does a can of Coca-Cola cost in 2045 ?
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document.write( "1960 to 2045 = 85 years
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document.write( "C(85) = 0.10*e^(0.0576*85)
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document.write( "I'll leave that calculation to you.
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document.write( "Cheers
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document.write( "Stan H.
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