document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=90617>Question 90617</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Martha leaves home at 9:am, bicycling at a rate of 24 mi/h. Two hours later, John leaves, driving at the rate of 48 mi/h. At what time will John catch up with Marth?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #65784 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=65784\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let t=Martha's time ... John's time is 2 hr less ... John catches up when the distances are equal ... (rate)(time)=distance\r<BR>\n" );
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document.write( "24t=48(t-2) ... 24t=48t-96 ... -24t=-96 ... t=4 ... John catches up at 1:00 PM </SPAN>\n" );
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