document.write( "Question 1042713: one number is three times another and their product is equal to their sum increased by fifty five. Find the numbers \n" ); document.write( "
Algebra.Com's Answer #657745 by macston(5194)\"\" \"About 
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\n" ); document.write( "y=one number; x=another number
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\n" ); document.write( "\"y=3x\"
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\n" ); document.write( "\"xy=x%2By%2B55\"
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\n" ); document.write( "\"x%283x%29=x%2B3x%2B55\"
\n" ); document.write( "\"3x%5E2=4x%2B55\"
\n" ); document.write( "\"3x%5E2-4x-55=0\"
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Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"3x%5E2%2B-4x%2B-55+=+0\") has the following solutons:
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\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%28-4%29%5E2-4%2A3%2A-55=676\".
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\n" ); document.write( " Discriminant d=676 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28--4%2B-sqrt%28+676+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"x%5B1%5D+=+%28-%28-4%29%2Bsqrt%28+676+%29%29%2F2%5C3+=+5\"
\n" ); document.write( " \"x%5B2%5D+=+%28-%28-4%29-sqrt%28+676+%29%29%2F2%5C3+=+-3.66666666666667\"
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\n" ); document.write( " Quadratic expression \"3x%5E2%2B-4x%2B-55\" can be factored:
\n" ); document.write( " \"3x%5E2%2B-4x%2B-55+=+3%28x-5%29%2A%28x--3.66666666666667%29\"
\n" ); document.write( " Again, the answer is: 5, -3.66666666666667.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+3%2Ax%5E2%2B-4%2Ax%2B-55+%29\"

\n" ); document.write( "\n" ); document.write( "x=5.00 or -3.66667
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\n" ); document.write( "If x=5:
\n" ); document.write( "y=3x
\n" ); document.write( "y=3(5)
\n" ); document.write( "y=15
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\n" ); document.write( "If x=-3.66667
\n" ); document.write( "y=3x
\n" ); document.write( "y=3(-3.66667)
\n" ); document.write( "y=-11
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\n" ); document.write( "ANSWER: The two numbers are 5 and 15 or -3.66667 and -11
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